THERE ARE TWO special triangles in trigonometry. One is the 30°-60°-90° triangle. The other is the isosceles right triangle. They are special because with simple geometry we can know the ratios of their sides, and therefore solve any such triangle.

Note that the smallest side, 1, is opposite the smallest angle, 30°; while the largest side, 2, is opposite the largest angle, 90°. (Theorem 6). (For, 2 is larger than

. Also, while 1 :

: 2 correctly corresponds to the sides opposite 30°-60°-90°, many find the sequence 1 : 2 :

easier to remember.)

Here are examples of how we take advantage of knowing those ratios. First, we can evaluate the functions of 60° and 30°.

Answer. For any problem involving a 30°-60°-90° triangle, the student should not use a table. The student should sketch the triangle and place the ratio numbers.

Answer. According to the property of cofunctions, sin 30° is equal to cos 60°. sin 30° = ½.

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1 : 2: SqRt 3

The cotangent is the ratio of the adjacent side to the opposite.

Therefore, on inspecting the figure above, cot 30° =

= .

Or, more simply, cot 30° = tan 60°.

As for the cosine, it is the ratio of the adjacent side to the hypotenuse. Therefore,

cos 30° =

= ½

Before we come to the next Example, here is how we relate the sides and angles of a triangle:

If an angle is labeled capital A, then the side opposite will be labeled small a. Similarly for angle B and side b, angle C and side c.

Example 3. Solve the right triangle ABC if angle A is 60°, and side AB is 10 cm.

Solution. To solve a triangle means to know all three sides and all three angles. Since this is a right triangle and angle A is 60°, then the remaining angle B is its complement, 30°.

Again, in every 30°-60°-90° triangle, the sides are in the ratio 1 : 2 :

, as shown on the left.

When we know the ratios of the sides, then to solve a triangle we do not require the trigonometric functions or the Pythagorean theorem. We can solve it by the method of similar figures.

Now, the sides that make the equal angles are in the same ratio. Proportionally,

To produce 10, 2 has been multiplied by 5. Therefore,

will also be multiplied by 5. BC is 5

cm.

In other words, since one side of the standard triangle has been multiplied by 5, then every side will be multiplied by 5.

Again: When we know the ratio numbers, then to solve the triangle the student should use this method of similar figures, not the trigonometric functions.

(In Topic 10, we will solve right triangles whose ratios of sides we do not know.)

Problem 3. In the right triangle DFE, angle D is 30° and side DF is 3 inches. How long are sides d and f ?

1 : 2: SqRt 3

The student should draw a similar triangle in the same orientation. Then see that the side corresponding to was multiplied by .

Therefore, each side will be multiplied by . Side d will be
1 = . Side f will be 2.

Problem 4. In the right triangle PQR, angle P is 30°, and side r is 1 cm. How long are sides p and q ?

Problem 5. Solve the right triangle ABC if angle A is 60°, and the hypotenuse is 18.6 cm.

The area A of any triangle is equal to one-half the sine of any angle times the product of the two sides that make the angle. (Topic 2, Problem 6.)

In an equilateral triangle each side is s , and each angle is 60°. Therefore,

A = ½ sin 60°s².

Since sin 60° = ½,

A = ½· ½ s² = ¼s².

Problem 7. Prove: The area A of an equilateral triangle inscribed in a circle of radius r, is

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The story is a modern-day retelling of the classic Korean folktale . The plot revolves around literature professor Shim Hak-kyu, who is forced to leave Seoul and teach in a small, rural town after being caught in a sex scandal. There, he meets Deok-yi, a young, naive ticket seller at a local amusement park. Despite being a married man with a daughter, Hak-kyu begins a passionate affair with her.

Eight years later, Hak-kyu is a successful but lonely writer who is gradually going blind. Deok-yi returns to his life under the alias Se-jung , moving in next door to exact a meticulously planned revenge on him and his daughter. Cast and Crew

The story is divided into two distinct chapters, separated by an eight-year gap. Part 1: The Affair (Present) Scandal-ridden literature professor Shim Hak-kyu

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[Phase 1: Passion] [Phase 2: Betrayal] [Phase 3: Vengeance] Hak-kyu (Professor) + Deokee (Naive Girl) --> Hak-kyu abandons Deokee for Seoul --> Deokee returns 8 years later (Steamy small-town affair) (Tragedy strikes Deokee's family) (Targeting the blind professor) The Affair and Betrayal

The film revolves around Shim Hak-kyu (played by Jung Woo-sung), a university professor who is banished to a small provincial town due to a sexual scandal. Bored and detached, he starts an intense affair with Deok-yi (played by Esom), a naive young woman working at a local theme park. The story is a modern-day retelling of the

The film is explicitly framed as a modern retelling of the classic Korean folktale . While the original story is a tale of a daughter's ultimate devotion to her blind father, Scarlet Innocence inverts this dynamic entirely. It replaces devotion with obsessive passion and then destructive revenge, using the source material as a dark, psychological mirror to explore how love can curdle into something far more sinister. This subversion of a well-known cultural narrative adds a layer of tragic depth for Korean audiences who are familiar with the original.

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as Shim Hak-kyu, a disgraced university professor.

: The story is split into two distinct time periods. The first half focuses on a passionate, illicit affair in a small rural town, while the second half—set eight years later—shifts into a "fatal attraction" revenge thriller.

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Problem 8. Prove: The angle bisectors of an equilateral triangle meet at a point that is two thirds of the distance from the vertex of the triangle to the base.

Let ABC be an equilateral triangle, let AD, BF, CE be the angle bisectors of angles A, B, C respectively; then those angle bisectors meet at the point P such that AP is two thirds of AD.

For, since the triangle is equilateral and BF, AD are the angle bisectors, then angles PBD, PAE are equal and each 30°;
and the side BD is equal to the side AE, because in an equilateral triangle the angle bisector is the perpendicular bisector of the base.

But AP = BP, because triangles APE, BPD are conguent, and those are the sides opposite the equal angles.
Therefore, AP = 2PD.
Therefore AP is two thirds of the whole AD.
Which is what we wanted to prove.

Here is the proof that in a 30°-60°-90° triangle the sides are in the ratio 1 : 2 :

. It is based on the fact that a 30°-60°-90° triangle is half of an equilateral triangle.

Draw the equilateral triangle ABC. Then each of its equal angles is 60°. (Theorems 3 and 9)

Draw the straight line AD bisecting the angle at A into two 30° angles.
Then AD is the perpendicular bisector of BC (Theorem 2). Triangle ABD therefore is a 30°-60°-90° triangle.

Therefore in a 30°-60°-90° triangle the sides are in the ratio 1 : 2 :

; which is what we set out to prove.

Corollary. The square drawn on the height of an equalateral triangle is three fourths of the square drawn on the side.